Manganese is present in the highest oxidation state in:
- AMnO₂
- BKMnO₄
- CMn₂(CO)₁₀
- DMnO₄²⁻
Show answer and explanation
Correct answer: (b) KMnO₄
Explanation
Taking oxygen as −2 and potassium as +1, the oxidation state (x) of manganese in each is:
- MnO₂: x + 2(−2) = 0, so x = +4;
- KMnO₄: +1 + x + 4(−2) = 0, so x = +7;
- Mn₂(CO)₁₀: CO is a neutral ligand, so x = 0;
- MnO₄²⁻ (manganate): x + 4(−2) = −2, so x = +6.
So manganese is in its highest oxidation state, +7, in potassium permanganate. This is also the highest state manganese shows, which is why KMnO₄ is a strong oxidising agent.