Chemistry PYQ 104 of 346 · Reactions & Catalysis

Manganese is present in the highest oxidation state in:

  1. AMnO₂
  2. BKMnO₄
  3. CMn₂(CO)₁₀
  4. DMnO₄²⁻

BPSC Assistant Section Officer Prelims 2025

Show answer and explanation

Correct answer: (b) KMnO₄

Explanation

Taking oxygen as −2 and potassium as +1, the oxidation state (x) of manganese in each is:

  • MnO₂: x + 2(−2) = 0, so x = +4;
  • KMnO₄: +1 + x + 4(−2) = 0, so x = +7;
  • Mn₂(CO)₁₀: CO is a neutral ligand, so x = 0;
  • MnO₄²⁻ (manganate): x + 4(−2) = −2, so x = +6.

So manganese is in its highest oxidation state, +7, in potassium permanganate. This is also the highest state manganese shows, which is why KMnO₄ is a strong oxidising agent.

Practise this questionAll 346 Chemistry PYQs